Fundamentholfundamenthol

Nucleic Acids

ChemistryBiomoleculesFor JEE aspirants

Nucleic acids, DNA and RNA, are polymers of nucleotides that store genetic information and direct the making of proteins. These notes on nucleic acids cover their sugars, bases and phosphate, nucleosides and nucleotides, the phosphodiester backbone, Chargaff's rules, the Watson-Crick double helix, replication, transcription, translation and the genetic code, with every structure drawn. They end with vitamins and hormones, the other biomolecules in the syllabus. The topic is asked every year in NEET and JEE Main.

On this page1Components2Nucleotides3Backbone4Double helix5DNA vs RNA6Replication7Gene to protein8Vitamins, hormones9Mind map10Examples
Key Formulas - Quick Reference
  1. ★ Must learn Nucleotide = nitrogen base + pentose sugar + phosphate; nucleoside = base + sugar; nucleic acid = polynucleotide.
  2. Sugar: RNA has -D-ribose; DNA has -D-2-deoxyribose (H in place of OH at C-2′).
  3. ★ Must learn Bases: purines A, G; pyrimidines C, T (DNA) and U (RNA). Thymine is 5-methyluracil.
  4. Base to sugar: N-1 of a pyrimidine or N-9 of a purine joins C-1′ by a -N-glycosidic bond; nucleotides join by 3′,5′-phosphodiester bonds.
  5. ★ Must learn Chargaff's rules (DNA): A = T and G = C, so purines = pyrimidines (A + G = C + T).
  6. ★ Must learn Pairing: A=T by 2 H-bonds, G≡C by 3 H-bonds; the strands are complementary and antiparallel.
  7. Double helix: right-handed, about 2 nm wide, 3.4 nm per turn with 10 base pairs (0.34 nm per pair).
  8. ★ Must learn Central dogma: DNA DNA (replication); DNA mRNA (transcription); mRNA protein (translation); RNA DNA in retroviruses.
  9. ★ Must learn Codon = 3 bases; codons; AUG = Met (start); UAA, UAG, UGA = stop.
  10. Vitamins: fat-soluble A, D, E, K (stored); water-soluble B group and C (not stored, except ).

1. What Are Nucleic Acids?

Every generation of a species resembles its ancestors. The particles in the nucleus of a cell that carry heredity are the chromosomes, made of proteins and another kind of biomolecule: the nucleic acids. Nucleic acids are biologically important polymers present in all living cells. Their repeating unit is the nucleotide, so they are also called polynucleotides.

There are two types of nucleic acids:

  • DNA (deoxyribonucleic acid), the store of genetic information.
  • RNA (ribonucleic acid), which uses that information to make proteins.

2. Chemical Composition

Complete hydrolysis of DNA or RNA gives three kinds of product: a pentose sugar, phosphoric acid and nitrogen-containing heterocyclic bases.

2.1 Phosphate group

Phosphoric acid, , is present in the chain as a phosphate group, , bonded to hydroxyl groups of the sugars as a phosphate ester. At the pH of the cell its OH groups are ionised, which gives nucleic acids their acidic, negatively charged character.

2.2 Sugars

Two sugars are found, both as five-membered (furanose) rings (Figure 1):

  • RNA contains -D-ribose, .
  • DNA contains -D-2-deoxyribose, , which has H instead of OH at C-2. This one missing oxygen gives DNA its name.
Sugars and phosphate in nucleic acids Haworth structures of beta-D-ribose, the sugar of RNA, and beta-D-2-deoxyribose, the sugar of DNA, with the C-2 position highlighted, beside phosphoric acid. O OH H H OH H OH HOH2C H 1 2 3 4 O OH H H H H OH HOH2C H 1 2 3 4 P O HO OH OH β-D-ribose (RNA) OH at C-2 β-D-2-deoxyribose (DNA) H at C-2: one O fewer phosphoric acid present as phosphate
Figure 1: RNA contains -D-ribose and DNA contains -D-2-deoxyribose, which has H instead of OH at C-2. Both are five-membered (furanose) rings.

2.3 Nitrogen bases

The bases are of two types (Figure 2):

  • Purines (two fused rings): adenine (A) and guanine (G), found in both DNA and RNA.
  • Pyrimidines (one ring): cytosine (C), in both; thymine (T), only in DNA; and uracil (U), only in RNA.
The five nitrogen bases of nucleic acids Structures of the purines adenine and guanine and the pyrimidines cytosine, thymine and uracil, each with the ring nitrogen that bonds to the sugar shaded, and the methyl group that turns uracil into thymine marked. PURINES: two fused rings PYRIMIDINES: one ring NH2 N N H N N adenine (A) DNA and RNA O N H H2N N N N H guanine (G) DNA and RNA NH2 N O N H cytosine (C) DNA and RNA N H O N H O thymine (T) DNA only O N H O N H uracil (U) RNA only shaded N (N-9 of purines, N-1 of pyrimidines): its H is replaced by C-1′ of the sugar thymine = 5-methyluracil (methyl shaded)
Figure 2: DNA uses A, G, C and T; RNA uses A, G, C and U. Purines have two fused rings, pyrimidines one, and thymine differs from uracil only by a methyl group at C-5.
ComponentDNARNA
Sugar-D-2-deoxyribose-D-ribose
Purine basesadenine (A), guanine (G)adenine (A), guanine (G)
Pyrimidine basescytosine (C), thymine (T)cytosine (C), uracil (U)
Phosphatephosphoric acid residuephosphoric acid residue
Exam Trick

"Pure As Gold": the PURines are Adenine and Guanine (two rings). The rest are pyrimidines: "CUT the Py", C, U, T (one ring). DNA keeps T, RNA swaps it for U.

Key idea
DNA: A, G, C, T on 2-deoxyribose. RNA: A, G, C, U on ribose. Both use phosphate; purines have two rings, pyrimidines one.

3. Nucleosides and Nucleotides

A nucleoside contains only two of the three components: a pentose sugar and a nitrogen base. N-1 of a pyrimidine or N-9 of a purine is joined to C-1′ of the sugar (ribose or deoxyribose) by a -linkage, the N-glycosidic bond. Sugar carbons are numbered with primes (1′ to 5′) to tell them apart from the atoms of the base. Depending on the sugar, nucleosides are ribonucleosides or deoxyribonucleosides.

A nucleotide contains all three components. When the C-5′ OH of a nucleoside is esterified with phosphoric acid, the product is a nucleotide, so nucleotides are nucleoside monophosphates. They too are ribonucleotides or deoxyribonucleotides. Cytidine monophosphate (CMP), for example, is cytosine + ribose + phosphate (Figure 3).

Structure of a nucleoside and a nucleotide A pentose sugar ring with primed numbering carries a nitrogen base at C-1 prime through a beta N-glycosidic bond and a phosphate group on the C-5 prime oxygen; the base plus sugar is a nucleoside and base plus sugar plus phosphate is a nucleotide. O H H OH H OH H 1′ 2′ 3′ 4′ BASE H2C 5′ O P O O− −O β-N-glycosidic bond phosphoester bond (at C-5′) OH (RNA) or H (DNA) at C-2′ nucleoside = base + sugar nucleotide = base + sugar + phosphate
Figure 3: A nucleoside joins a base to C-1′ of the sugar; adding a phosphate ester on C-5′ makes a nucleotide. Sugar atoms are numbered with primes to tell them from base atoms.
BaseRibonucleoside (RNA)Deoxyribonucleoside (DNA)Nucleotide (5′-monophosphate)
AdenineadenosinedeoxyadenosineAMP, dAMP
GuanineguanosinedeoxyguanosineGMP, dGMP
CytosinecytidinedeoxycytidineCMP, dCMP
Uraciluridine(not in DNA)UMP
Thymine(not in RNA)thymidinedTMP
Nucleosidebase + sugar
N-glycosidic bond at C-1′
adenosine, thymidine
no phosphate
Nucleotidebase + sugar + phosphate
phosphate ester at C-5′
AMP, dTMP, ATP
monomer of nucleic acids

Nucleotides also do other jobs in the cell. Adenosine triphosphate (ATP), with three phosphate groups on C-5′, is the cell's main carrier of chemical energy.

Structure of ATP Adenine joined through N-9 to C-1 prime of ribose makes adenosine; a chain of three phosphate groups on the C-5 prime oxygen makes adenosine triphosphate. Brackets show adenosine, AMP, ADP and ATP, and the two phosphoanhydride bonds that release energy on hydrolysis are marked. NH2 N N N N ribose O 1′ CH2 5′ O P α O P β O P γ O- adenosine (nucleoside) = adenine + ribose AMP = adenosine + 1 P ADP = adenosine + 2 P ATP = adenosine + 3 P = phosphoanhydride bond (energy-rich) ATP + H2O → ADP + Pi releases about 30.5 kJ mol-1: the cell's energy currency
Figure 4: ATP is a nucleotide with two extra phosphates. Breaking the terminal phosphoanhydride bond gives ADP and releases about 30.5 kJ per mole, which drives most energy-requiring steps in the cell.
Quick Recall: tap to check
Adenine + ribose is called?
Adenosine, a nucleoside (no phosphate).
Which sugar carbon carries the base, and which the phosphate?
The base is on C-1′, the phosphate on C-5′.
How many energy-rich phosphoanhydride bonds does ATP have?
Two: between the and , and the and phosphates.

4. Polynucleotides: The Primary Structure

Nucleotides are joined into a chain through phosphate groups. The phosphate on C-5′ of one nucleotide forms an ester with the C-3′ OH of the sugar of the next, giving a 3′,5′-phosphodiester linkage and releasing water. Repeating this builds a sugar-phosphate backbone, with the bases hanging from C-1′ of each sugar (Figure 5).

  • One end of the chain has a free C-5′ group (the 5′ end) and the other a free C-3′ OH (the 3′ end). Sequences are written from the 5′ end to the 3′ end.
  • A chain of nucleotides contains phosphodiester links.
  • The sequence in which the bases are attached to the sugar-phosphate backbone is the primary structure of the nucleic acid.
A polynucleotide strand Four nucleotides with bases A, C, G and T joined through their sugars by phosphate groups, forming a sugar-phosphate backbone with a 5 prime end and a 3 prime end. P A P C P G P T OH 5′ end 3′ end sequence read 5′ → 3′: 5′-ACGT-3′ 3′,5′-phosphodiester link: C-3′–O–P–O–C-5′ backbone = sugar-phosphate-sugar-phosphate; bases hang from C-1′
Figure 5: Nucleotides join by 3′,5′-phosphodiester links between the C-3′ OH of one sugar and the C-5′ phosphate of the next. The order of bases is the primary structure.
Key idea
Nucleotides join C-3′ to C-5′ through phosphodiester links; the base sequence, read 5′ → 3′, is the primary structure.

5. Structure of DNA and RNA

5.1 Chargaff's rules

Erwin Chargaff analysed the base composition of DNA from many organisms and found that:

  • the amount of adenine equals the amount of thymine (A = T), and the amount of guanine equals the amount of cytosine (G = C);
  • so the total purines equal the total pyrimidines: A + G = C + T;
  • the ratio (A + T)/(G + C) differs from one species to another, but is the same in all cells of one species.

5.2 The Watson-Crick double helix

In 1953 James Watson and Francis Crick proposed that DNA is a duplex: two polynucleotide strands coiled round each other in a double helix. The sugar-phosphate backbones are on the outside and the bases are stacked inside. Each base on one strand is paired with a base on the other by hydrogen bonds:

  • Adenine pairs with thymine through two hydrogen bonds (A=T), and guanine pairs with cytosine through three (G≡C). A purine always faces a pyrimidine, which keeps the width of the helix constant (Figure 6). This pairing explains Chargaff's rules.
  • The two strands are complementary, not identical: the sequence of one fixes the sequence of the other.
  • The strands run in opposite directions (antiparallel): one 5′ to 3′, the other 3′ to 5′.
  • The helix is right-handed, about 2 nm wide, with one complete turn every 3.4 nm and 10 base pairs per turn (Figure 6).
Complementary base pairing in DNA Watson-Crick base pairs: adenine and thymine held by two hydrogen bonds, and guanine and cytosine held by three hydrogen bonds, with each base attached to a sugar. NH2 N N N N N O HN O sugar sugar O NH NH2 N N N H2N N O N sugar sugar A=T: 2 hydrogen bonds G≡C: 3 hydrogen bonds
Figure 6: A purine always pairs with a pyrimidine: A with T through two H-bonds and G with C through three. This is why A = T and G = C in DNA (Chargaff's rule).
The DNA double helix with major and minor grooves Two antiparallel sugar-phosphate strands, computed as sine curves offset along the axis, wind round one axis as a right-handed double helix joined by ten base pairs per turn. Because the strands are offset, the gaps between them alternate as a narrow minor groove and a wide major groove. One turn is 3.4 nanometres and the helix is 2 nanometres wide. minor groove major groove one turn (pitch) = 3.4 nm = 10 base pairs; rise 0.34 nm per pair 2 nm 5′ 3′ 3′ 5′ A=T pair G≡C pair strands run 5′→3′ in opposite directions
Figure 7: The two backbones are offset along the axis (here by nm), so the gaps between them alternate: a narrow minor groove and a wide major groove. Ten base pairs, each nm apart, make one 3.4 nm turn.
Exam Trick

"AT two, GC three." A-T pairs have two H-bonds and G-C pairs three, so DNA richer in G and C holds its strands together more strongly and needs a higher temperature to separate them. Pair a purine with a pyrimidine ("big with small"): A with T, G with C.

5.3 Structure of RNA

RNA is similar to DNA in its backbone but is usually a single strand, which may fold back on itself where short stretches of complementary bases pair (with U pairing with A). RNA molecules are of three types, with different functions:

  • Messenger RNA (mRNA) carries the genetic message from DNA to the ribosomes.
  • Ribosomal RNA (rRNA) forms the ribosomes, with proteins, where proteins are made.
  • Transfer RNA (tRNA) brings the right amino acid to the ribosome and reads the codon.
Key idea
A pairs with T by two H-bonds, G with C by three; the two antiparallel strands are complementary, which is why A = T and G = C.
Quick Recall: tap to check
A DNA sample has 18% guanine. What is its adenine content?
C = 18%, so A + T = 64% and A = 32%.
Complement of 5′-GATC-3′, written 5′ → 3′?
5′-GATC-3′ (it is its own complement, a palindrome).
Why is the helix width constant along its length?
Every pair is one purine plus one pyrimidine, so every rung is the same length.

6. DNA and RNA Compared

FeatureDNARNA
Sugar2-deoxyriboseribose
Pyrimidine basescytosine and thyminecytosine and uracil
Structuredouble-stranded helixsingle strand (may fold on itself)
Base pairing ruleA = T, G = C (Chargaff)no such equality
Locationmainly in the nucleus (also mitochondria, chloroplasts)made in the nucleus; works mainly in the cytoplasm
Functionstores and passes on hereditary information; replicatesdirects protein synthesis (mRNA, rRNA, tRNA)
Sizevery large moleculessmaller molecules
JEE Advanced

Why DNA, not RNA, stores the genes. The 2′-OH of ribose sits next to the phosphodiester link and can attack its own phosphorus, cutting the chain, so RNA is hydrolysed easily, fastest in alkali. 2-Deoxyribose has no 2′-OH, so DNA is far more stable. Thymine helps too: cytosine slowly loses its to become uracil, and because DNA normally contains no uracil, any U found in DNA is recognised as damage and repaired.

7. Biological Functions of Nucleic Acids

DNA is the chemical basis of heredity and is responsible for keeping the identity of each species over millions of years. It can replicate (copy itself) during cell division, passing identical DNA to the daughter cells, and it holds the message for making proteins. The proteins are actually made by the RNA molecules of the cell, under DNA's direction.

7.1 Replication

Replication is the process by which one DNA molecule produces two identical copies of itself. It is enzyme-catalysed. The two strands of the helix unwind, and each strand acts as a template (pattern) for a new strand: nucleotides line up by base pairing (A with T, G with C) and are joined by DNA polymerase. Each new strand is the exact complement of its template, so both daughter molecules are copies of the original, each keeping one old strand (semi-conservative replication, Figure 8). In this way hereditary characteristics are passed from one cell to the next.

Semi-conservative replication of DNA A parent DNA double helix unwinds at a replication fork; each old strand acts as a template for a new complementary strand, giving two daughter molecules that each contain one old and one new strand. parent DNA fork daughter DNA 1: old strand + new strand daughter DNA 2: new strand + old strand original (template) strand new complementary strand (DNA polymerase)
Figure 8: In replication the two strands separate and each templates a new partner, so every daughter DNA keeps one original strand (semi-conservative replication).

Meselson and Stahl proved the semi-conservative model in 1958 by growing bacteria on heavy nitrogen and then on light nitrogen, and separating the DNA by density:

Semi-conservative replication shown by density bands Four centrifuge tubes of DNA after zero, one, two and three generations: all heavy, then all hybrid, then half hybrid and half light, then one quarter hybrid and three quarters light. light 14N/14N hybrid 15N/14N heavy 15N/15N 100% generation 0 all heavy 100% generation 1 all hybrid 50% 50% generation 2 1 hybrid : 1 light 25% 75% generation 3 1 hybrid : 3 light DNA bands in a CsCl density gradient (grown in 15N, then moved to 14N) the two original heavy strands survive: hybrid molecules stay at 2, their share halves each time
Figure 9: The Meselson-Stahl result. After one generation every molecule is hybrid (one old heavy strand, one new light strand); after generations only 2 of molecules stay hybrid. Only semi-conservative replication gives this pattern.

7.2 Protein synthesis: transcription and translation

Transcription is the synthesis of RNA (mRNA) on a DNA template. It resembles replication, with two differences: ribonucleotides (not deoxyribonucleotides) assemble along the unwound template, and uracil (U) takes the place of thymine (T). Nucleic acid chains are always built in the 5′ 3′ direction, here by the enzyme RNA polymerase. In this way DNA passes its genetic code to mRNA. The mRNA then separates from the DNA and moves from the nucleus to the cytoplasm, where it acts as the template for protein synthesis, and the DNA returns to its double helix.

Translation is the synthesis of protein, directed by mRNA in the cytoplasm with the help of tRNA and ribosomes (RNA-protein particles). The mRNA attaches to a ribosome and dictates the amino acid sequence. Its bases are read in threes: each triplet, called a codon, codes for one amino acid. Each tRNA carries an amino acid and an anticodon that pairs with the codon, so the amino acids are placed in the right order and joined by peptide bonds. When the chain is complete it is released from the ribosome. Protein synthesis is fast: about 20 amino acids are added every second.

From DNA to protein: the central dogma and codons Flow of genetic information: DNA replicates, is transcribed into mRNA by RNA polymerase, and mRNA is translated into protein on ribosomes; below, a template DNA sequence, its mRNA codons AUG GGU UUC UAA and the amino acids methionine, glycine, phenylalanine and stop. DNA mRNA protein transcription translation RNA polymerase, nucleus ribosome + tRNA, cytoplasm reverse transcription (retroviruses) replication template DNA 3′ TAC CCA AAG ATT 5′ mRNA 5′ AUG GGU UUC UAA 3′ protein Met (start) Gly Phe stop each codon (three bases) codes for one amino acid; the mRNA is complementary to the template, with U in place of T
Figure 10: DNA mRNA protein. The mRNA copies the template strand's complement, and each three-base codon is read as one amino acid.

Translation always runs one way (mRNA to protein), but transcription can sometimes be reversed: in retroviruses such as HIV, RNA is copied into DNA by the enzyme reverse transcriptase (reverse transcription).

ReplicationDNA → DNA
both strands are templates
DNA polymerase; A, G, C, T
whole chromosome, before cell division
TranscriptionDNA → mRNA
one strand (template) is read
RNA polymerase; A, G, C, U
one gene at a time

7.3 The genetic code

A segment of DNA that carries the information for one protein is a gene. The relationship between nucleotide triplets and amino acids is the genetic code. With four bases, triplets give codons, more than enough for 20 amino acids. So most amino acids have more than one codon (the code is degenerate), and three codons are stop signals.

Codon (mRNA)Amino acidNote
AUGmethionine (Met)also the start signal
GGU, GGC, GGA, GGGglycine (Gly)four codons, one amino acid
UUU, UUCphenylalanine (Phe)
CCAproline (Pro)
UAA, UAG, UGAnonestop signals

Every sequence question on this page is solved in the same order, shown as a flowchart:

Flowchart for reading a gene from DNA to peptide Decision flowchart: if the given strand is the template, the mRNA is its complement written antiparallel; if it is the coding strand, the mRNA is the same sequence with uracil for thymine. The mRNA is read five prime to three prime in triplets from AUG, each codon giving one amino acid, until a stop codon releases the chain. yes no yes DNA sequence given Is it the template strand? mRNA = complement of it: A→U, T→A, G→C, C→G, written antiparallel Coding strand: mRNA has the same sequence with U for T Read the mRNA 5′→3′ in triplets, starting at AUG (Met) Look up each codon: one codon = one amino acid Stop codon? UAA, UAG, UGA Chain released: peptide complete no: next
Figure 11: Flowchart: decide first which strand you have. The template gives the mRNA by base pairing; the coding strand gives it by swapping T for U. Then read codons from AUG until UAA, UAG or UGA.
Exam Trick

"Template is the mirror, coding strand is the twin": mRNA is complementary to the template strand but has the same sequence as the coding strand, with U in place of T.

Key idea
DNA copies itself semi-conservatively, is transcribed into mRNA, and mRNA is translated three bases (one codon) at a time from AUG to a stop codon.
Quick Recall: tap to check
Which enzyme makes mRNA on a DNA template?
RNA polymerase (DNA polymerase copies DNA).
mRNA codon for the template triplet 3′-TAC-5′?
5′-AUG-3′, methionine, the start codon.
What fraction of DNA is hybrid after 2 generations in the Meselson-Stahl experiment?
Half: 2 of 4 molecules.

8. Other Biomolecules: Vitamins and Hormones

8.1 Vitamins

Some organic compounds are needed in the diet in small amounts to carry out particular biological functions, for normal health, growth and nutrition. Their lack causes specific diseases. These compounds are vitamins. Most cannot be made by the body (plants can make almost all of them), so they must come from food. Vitamins are named by letters and subscripts, such as A, , , , , C, D, E and K. Too much of a vitamin is also harmful, so vitamin pills should be taken only on a doctor's advice.

  • Fat-soluble vitamins, A, D, E and K, dissolve in fats and oils but not in water. They are stored in the liver and adipose (fat-storing) tissue.
  • Water-soluble vitamins, the B group and C, must be supplied regularly, because they are readily excreted in urine and cannot be stored in the body. Vitamin is the exception: it is stored in the liver.
VitaminSourcesDeficiency disease
A (retinol)fish liver oil, carrots, butter, milkxerophthalmia (hardening of the cornea), night blindness
(thiamine)yeast, milk, green vegetables, cerealsberi-beri (loss of appetite, retarded growth)
(riboflavin)milk, egg white, liver, kidneycheilosis (fissures at the corners of the mouth and lips), digestive disorders, burning sensation of the skin
(pyridoxine)yeast, milk, egg yolk, cereals, gramsconvulsions
(cyanocobalamin)meat, fish, egg, curdpernicious anaemia (RBCs deficient in haemoglobin)
C (ascorbic acid)citrus fruits, amla, green leafy vegetablesscurvy (bleeding gums)
D (calciferol)exposure to sunlight, fish, egg yolkrickets (bone deformities in children), osteomalacia (soft bones and joint pain in adults)
E (tocopherols)vegetable oils such as wheat germ oil and sunflower oilincreased fragility of RBCs, muscular weakness
K (phylloquinone)green leafy vegetablesincreased blood clotting time
Fat-soluble and water-soluble vitamins with deficiency diseases Two panels: the fat-soluble vitamins A, D, E and K, stored in the liver and fat tissue, and the water-soluble vitamins B1, B2, B6, B12 and C, excreted in urine except B12, each with the disease caused by its deficiency. Fat-soluble: A, D, E, K stored in liver and fat tissue A night blindness, xerophthalmia D rickets; osteomalacia (adults) E fragile RBCs, muscle weakness K slow blood clotting Water-soluble: B group, C excreted in urine (B12 is stored in liver) B1 beri-beri B2 cheilosis, skin burning B6 convulsions B12 pernicious anaemia C scurvy (bleeding gums)
Figure 12: Solubility decides storage. Fat-soluble A, D, E, K are stored, so an excess can be harmful; water-soluble B and C leave in urine and must be eaten regularly, except .

8.2 Hormones

Hormones are molecules that act as messengers between cells. They are made by the endocrine glands and poured directly into the bloodstream, which carries them to the site of action. Chemically they fall into three groups:

Chemical classExamplesRole
Steroidsestrogens, androgens (testosterone, estradiol, progesterone); glucocorticoids, mineralocorticoidssex characteristics and reproduction; metabolism, stress, salt and water balance
Polypeptidesinsulin, glucagon, endorphinsblood glucose control; pain relief
Amino acid derivativesepinephrine, norepinephrine (adrenaline, noradrenaline); thyroxineresponses to stimuli; rate of metabolism
  • Hormones keep the balance of biological activities in the body. Insulin and glucagon keep blood glucose within a narrow range; epinephrine and norepinephrine drive responses to outside stimuli; growth hormones and sex hormones control growth and development.
  • Thyroxine, made in the thyroid gland, is an iodinated derivative of the amino acid tyrosine. Too little thyroxine (hypothyroidism) causes lethargy and obesity; too much (hyperthyroidism) raises the body's activity. Low iodine in the diet causes hypothyroidism and enlargement of the thyroid gland (goitre), which is prevented by adding sodium iodide to table salt (iodised salt).
  • The adrenal cortex makes glucocorticoids, which control carbohydrate metabolism, modulate inflammation and help the body cope with stress, and mineralocorticoids, which control how much water and salt the kidneys excrete. Failure of the adrenal cortex causes Addison's disease (hypoglycaemia, weakness, greater sensitivity to stress), which is fatal unless treated with these hormones.
  • The gonads make the sex hormones. Testosterone gives male secondary characteristics (deep voice, facial hair, general build); estradiol gives female secondary characteristics and controls the menstrual cycle; progesterone prepares the uterus for the implantation of a fertilised egg.

9. The Whole Topic on One Page: Mind Map

The mind map collects the page: what nucleic acids are made of, how they pair, how the information flows, and the other biomolecules in the chapter.

Mind map of nucleic acids Mind map with eight branches: components, nucleosides and nucleotides, the phosphodiester backbone, base pairing and Chargaff's rule, the double helix, types of RNA, the flow of genetic information, and vitamins and hormones. Nucleic acids DNA and RNA Components base + pentose + phosphate purines: A, G (two rings) pyrimidines: C, T, U DNA: T, deoxyribose; RNA: U Units nucleoside = base + sugar nucleotide = + phosphate base at C-1′ (N-glycosidic) ATP: 3 phosphates, energy Backbone 3′,5′-phosphodiester links read 5′ → 3′ n units: n − 1 links Pairing A=T: 2 H-bonds G≡C: 3 H-bonds Chargaff: A = T, G = C purines = pyrimidines Double helix Watson-Crick, 1953 antiparallel, right-handed 2 nm wide, 3.4 nm per turn 10 bp per turn; two grooves RNA types mRNA: carries the code tRNA: brings amino acids rRNA: ribosomes Information flow replication: semi-conservative transcription: DNA → mRNA translation: mRNA → protein codon: 3 bases; 64 codons Vitamins, hormones fat-soluble A, D, E, K water-soluble B, C hormones: steroid, peptide, amino acid derived
Figure 13: Mind map: every branch follows from one fact, that A pairs with T (or U) and G with C.

10. Solved Examples

Solved Example 1
Chargaff's rule states that in the DNA of an organism
(A) the amount of adenine equals that of thymine, and the amount of guanine equals that of cytosine
(B) the amount of adenine equals that of guanine, and the amount of thymine equals that of cytosine
(C) the amount of adenine equals that of cytosine, and the amount of thymine equals that of guanine
(D) the amounts of all four bases are equal
Solution:

Answer: (A). A pairs with T and G with C, so A = T and G = C. It follows that the total purines equal the total pyrimidines (A + G = C + T), but the four bases are not generally equal.

Solved Example 2
What products are obtained on complete hydrolysis of (i) DNA and (ii) RNA?
Solution:

(i) DNA gives 2-deoxyribose, phosphoric acid and the bases adenine, guanine, cytosine and thymine.

(ii) RNA gives ribose, phosphoric acid and adenine, guanine, cytosine and uracil.

Solved Example 3
A sample of double-stranded DNA contains 30% adenine. Find the percentages of thymine, guanine and cytosine.
Solution:

By Chargaff's rule T = A = 30%, so A + T = 60%. The remaining 40% is shared equally by G and C: G = C = 20%.

Solved Example 4
One strand of a DNA segment has the sequence 5′-ATGCCA-3′. Write the sequence of the complementary strand.
Solution:

Pair A with T and G with C, and run the new strand the opposite way:

3′-TACGGT-5′, which written 5′ 3′ is 5′-TGGCAT-3′.

Solved Example 5
A DNA segment has 10 A-T pairs and 15 G-C pairs. How many hydrogen bonds hold its two strands together? Which would need a higher temperature to separate: this segment or one with 15 A-T and 10 G-C pairs?
Solution:

H-bonds . The other segment has . The first segment, richer in G-C pairs, has more H-bonds and needs a higher temperature to separate its strands.

Solved Example 6
Adenine + ribose + one phosphate group is
(A) adenosine
(B) adenosine monophosphate (AMP)
(C) adenosine triphosphate (ATP)
(D) deoxyadenosine
Solution:

Answer: (B). Base + sugar is the nucleoside adenosine; adding one phosphate at C-5′ gives the nucleotide AMP. ATP carries three phosphates, and deoxyadenosine has deoxyribose, not ribose.

Solved Example 7
How many phosphodiester links are present in (i) a single linear strand of 50 nucleotides and (ii) a linear double-stranded DNA of 50 base pairs?
Solution:

(i) . (ii) Each strand has 49 links, so .

Solved Example 8
Why must the genetic code use triplets of bases rather than pairs?
Solution:

Proteins use 20 amino acids. With four bases, single bases give only codes and pairs only , too few. Triplets give , enough for all 20 amino acids plus start and stop signals, with several codons for most amino acids.

Solved Example 9
The template strand of a gene reads 3′-TACCCAAAGATT-5′. Write the mRNA made from it and the peptide it codes for.
Solution:

mRNA is complementary to the template, with U for T: 5′-AUG GGU UUC UAA-3′. Reading codons: AUG = Met (start), GGU = Gly, UUC = Phe, UAA = stop. The peptide is Met-Gly-Phe (Figure 10).

Solved Example 10
Bacteria grown for many generations in (heavy) medium are moved to (light) medium. What fraction of the DNA molecules is hybrid () after one, two and three generations?
Solution:

Replication is semi-conservative, so the two original heavy strands survive intact and each ends up in a different molecule.

  • After 1 generation: 2 molecules, both hybrid (100% hybrid).
  • After 2 generations: 4 molecules, 2 hybrid and 2 light (50% hybrid).
  • After 3 generations: 8 molecules, 2 hybrid and 6 light (25% hybrid).
Solved Example 11
The sugar of DNA differs from that of RNA at
(A) C-1′
(B) C-2′
(C) C-3′
(D) C-5′
Solution:

Answer: (B). 2-Deoxyribose has H at C-2′ where ribose has OH.

Solved Example 12
Which vitamin is water-soluble but still stored in the liver?
(A) vitamin C
(B) vitamin
(C) vitamin
(D) vitamin D
Solution:

Answer: (C). Water-soluble vitamins are normally excreted in urine, but is stored in the liver. Vitamin D is fat-soluble.

Solved Example 13
Thyroxine is an iodinated derivative of which amino acid? What does a lack of iodine in the diet cause?
Solution:

Thyroxine is made from tyrosine. Too little iodine leads to hypothyroidism and enlargement of the thyroid gland (goitre), which is why table salt is iodised.

Solved Example 14
A 20 base-pair stretch of DNA is 40% G + C. The number of hydrogen bonds holding its two strands together is
(A) 40
(B) 48
(C) 52
(D) 60
Solution:

Answer: (B). 40% of 20 pairs are G-C: 8 pairs with 3 H-bonds each, 24. The other 12 pairs are A-T with 2 each, 24. Total .

Solved Example 15
One strand of a DNA molecule contains 20% A, 30% T, 10% G and 40% C. The percentage of A in the complementary strand is
(A) 20%
(B) 30%
(C) 10%
(D) 40%
Solution:

Answer: (B). Every T on the first strand faces an A on the second, so A in the complementary strand equals T in the first: 30%. Chargaff's A = T holds for the whole duplex, not for each strand separately.

Solved Example 16
How many phosphoester and phosphoanhydride bonds are present in one molecule of ATP?
Solution:

One phosphoester bond joins the -phosphate to the C-5′ oxygen of ribose. Two phosphoanhydride bonds (P-O-P) join to and to ; hydrolysing the terminal one gives ADP and releases about 30.5 kJ mol.

Practice Questions
  1. What is the difference between a nucleoside and a nucleotide?Answer: A nucleoside is base + sugar; a nucleotide is base + sugar + phosphate (a nucleoside monophosphate).
  2. Name the bases present in DNA and in RNA. Which base is found in only one of them?Answer: DNA: A, G, C, T; RNA: A, G, C, U. Thymine is only in DNA, and uracil only in RNA.
  3. The two strands of DNA are not identical but complementary. Explain.Answer: A always pairs with T and G with C by hydrogen bonds, so the sequence of one strand decides the sequence of the other.
  4. Write the two main functions of nucleic acids.Answer: DNA stores hereditary information and replicates to pass it on; RNA directs protein synthesis.
  5. A DNA sample contains 22% cytosine. What percentage of adenine does it contain?Answer: G = C = 22%, so A + T = 56% and A = 28%.
  6. Which carbon of the sugar joins the base, and which carbons form the phosphodiester link?Answer: The base joins C-1′; the phosphodiester link joins C-3′ of one sugar to C-5′ of the next.
  7. What is the role of mRNA, tRNA and rRNA in protein synthesis?Answer: mRNA carries the code (codons); tRNA brings amino acids and reads codons with its anticodon; rRNA, with proteins, forms the ribosome where peptide bonds are made.
  8. Why must vitamin C be supplied regularly in the diet?Answer: It is water-soluble, so it is excreted in urine and not stored in the body.
  9. Name the deficiency diseases caused by a lack of vitamins A, , C and D.Answer: A: xerophthalmia and night blindness; : beri-beri; C: scurvy; D: rickets (osteomalacia in adults).
  10. Which vitamins are fat-soluble, and where are they stored?Answer: A, D, E and K; they are stored in the liver and adipose tissue.
  11. What are hormones? Classify them by chemical nature, with one example of each class.Answer: Chemical messengers secreted by endocrine glands into the blood. Steroids (testosterone), polypeptides (insulin), amino acid derivatives (thyroxine, epinephrine).
  12. What are the roles of insulin and glucagon?Answer: Together they keep the blood glucose level within a narrow range: insulin lowers it, glucagon raises it.
  13. The base present in RNA but not in DNA is (A) adenine (B) guanine (C) uracil (D) thymineAnswer: (C).
  14. The number of hydrogen bonds between guanine and cytosine is (A) 1 (B) 2 (C) 3 (D) 4Answer: (C).

Common Mistakes to Avoid

Watch out
  • Mixing up nucleoside and nucleotide. The nucleoTide has the phosphaTe; the nucleoside is base + sugar only.
  • Putting uracil in DNA or thymine in RNA. DNA: A, G, C, T; RNA: A, G, C, U.
  • Swapping the H-bond counts. A=T has two hydrogen bonds and G≡C has three.
  • Reading Chargaff's rule as A = G. The equalities are A = T and G = C; only the totals A + G and C + T are equal.
  • Writing complementary strands in the same direction. The strands are antiparallel; write each sequence 5′ to 3′.
  • Saying deoxyribose lacks the OH at C-3′. It is missing at C-2′; the C-3′ OH is needed for the phosphodiester link.
  • Saying RNA is found only in the cytoplasm. It is made in the nucleus and works mainly in the cytoplasm.
  • Calling all hormones proteins. Many are steroids (testosterone) or amino acid derivatives (thyroxine, adrenaline).
  • Saying no water-soluble vitamin is stored. Vitamin is stored in the liver.

Frequently Asked Questions

What is the difference between DNA and RNA?

DNA contains 2-deoxyribose and the bases A, G, C and T, and is a double helix that stores hereditary information. RNA contains ribose and the bases A, G, C and U, is usually single-stranded, and directs protein synthesis as mRNA, tRNA and rRNA.

What is the difference between a nucleoside and a nucleotide?

A nucleoside is a nitrogen base joined to a pentose sugar through a -N-glycosidic bond at C-1′, for example adenosine. A nucleotide is a nucleoside with a phosphate group esterified at C-5′, for example adenosine monophosphate (AMP). Nucleotides are the repeating units of nucleic acids.

What is Chargaff's rule?

Chargaff's rule says that in double-stranded DNA the amount of adenine equals that of thymine, and the amount of guanine equals that of cytosine. So the total purines equal the total pyrimidines. The rule follows from base pairing: A always pairs with T, and G with C.

What is the structure of the DNA double helix?

Watson and Crick (1953) showed DNA is two antiparallel polynucleotide strands wound into a right-handed double helix. The sugar-phosphate backbones are outside and the bases pair inside, A with T by two H-bonds and G with C by three. One turn is 3.4 nm with ten base pairs.

What is a codon?

A codon is a sequence of three bases on mRNA that codes for one amino acid. Four bases give 64 possible codons, so most amino acids have several. AUG codes for methionine and also starts translation, while UAA, UAG and UGA are stop signals that end the protein chain.

Which vitamins are fat-soluble and which are water-soluble?

Vitamins A, D, E and K are fat-soluble and are stored in the liver and fat tissue. The B-group vitamins and vitamin C are water-soluble; they are excreted in urine and must be taken regularly, except vitamin , which the liver stores.

Which nucleic acid topics are most important for NEET?

NEET chemistry asks NCERT-line facts: components of DNA and RNA, the bases in each, nucleoside versus nucleotide, the phosphodiester link, Chargaff's rule and base pairing, the double helix, DNA versus RNA, and vitamin sources and deficiency diseases. The vitamin table is a frequent source of one-mark questions.

How are nucleic acids tested in JEE Main?

JEE Main asks about the sugar and bases in DNA and RNA, nucleoside versus nucleotide, the glycosidic and phosphodiester links, the number of H-bonds in A-T and G-C pairs, Chargaff-based percentage questions and which vitamins are water-soluble. Hormone questions test their chemical class, such as thyroxine being an amino acid derivative.

Previous year questions on Nucleic Acids

7 questions from past papers, each with a step-by-step solution.

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