Vector (or Cross) Product of Two Vectors
VECTOR (OR CROSS) PRODUCT OF TWO VECTORS
The vector product of two vectors and , denoted by , is defined as the vector , where is the angle between the vectors
and and is a unit vector perpendicular to both and (i.e., perpendicular to the plane of and ).The sense of is obtained by the right hand thumb rule i.e., and form a right-handed screw.
If we curl the fingers of our right hand from to through the smaller angle (keeping the initial point of and same), the thumb points in the direction of . In this case, ,and (or ), in that order are said to form a right handed system. It is evident that = absin.
Properties:
(non-commutative) (Distributive) are collinear (if none of is a zero vector) ;;;;; If then \overline a \, \times \overline b;= \,\left| {\begin{array}{*{20}{c}};{\hat i}{\hat j}{\hat k} \\;;{{a_1}}{{a_2}}{{a_3}} \\;;{{b_1}}{{b_2}}{{b_3}};\end{array}} \right|;;;;;;;;;;;= ;;;;;;;;Any vector perpendicular to the plane of is () where is a real number. Unit vector perpendicular to is denotes the area of the parallelogram OACB, whereas area of OAB = Area is also treated as a vector with its direction in the proper sense.
Illustration :;;;;;;;;;;;;; and are unit vectors and || = 4. If angle between and is cos–1 and , then show that; can be written as;;also find the value of . ;Solution:;;;;;;;;;;;;;;;;;;Since vector and (-2) are collinear, vector can be written as
16 + 4 – 4(4) (1) = 2(1)
2 = 16 4.
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