JEE Advanced 2022 Paper 1, Physics Section 1 Q3: Capacitors And Capacitance

JEE Advanced2022Paper 1Physics Section 1

In the following circuit $C_{1} = 12 μ F$ , $C_{2} = C_{3} = 4 μ F$ and $C_{4} = C_{5} = 2 μ F$ . The charge stored in $C_{3}$ is ____ $μ$ C.

Your answer

Solution

From the symmetry and topology of the circuit, the potential difference across $C_{3}$ equals the EMF of the smaller branch.

The potential difference across $C_{3}$ works out to 2 V (constant across the relevant nodes).

$Q_{3} = C_{3} \cdot V_{3} = 4 μ F \times 2 V = 8 μ C$ .

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