JEE Advanced 2022 Paper 2, Chemistry Section 1 Q4: Group 18 Elements: The Noble Gases

JEE Advanced2022Paper 2Chemistry Section 1

The reaction of Xe and O $_{2}$ F $_{2}$ gives a Xe compound P. The number of moles of HF produced by the complete hydrolysis of 1 mol of P is _______.

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Solution

Xenon reacts with dioxygen difluoride to give xenon tetrafluoride:

$Xe + 2 O_{2} F_{2} \to (P) XeF_{4} + 2 O_{2}$

Complete hydrolysis of XeF $_{4}$ proceeds as:

$6 XeF_{4} + 12 H_{2} O \to 4 Xe + 2 XeO_{3} + 24 HF + 3 O_{2}$

Per mole of XeF $_{4}$ : $24/6 = 4$ mol of HF are produced.

$∴$ Moles of HF = 4.

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JEE Advanced 2022 Paper 2, Chemistry Section 1 Q4: Group 18 Elements: The Noble Gases

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