Fundamentholfundamenthol
JEE Advanced2026Paper 2CHEM-II
Q.

The correct statement(s) regarding the periodic properties of elements is (are)

  1. A

    (A) Second ionization enthalpy of carbon atom is less than that of boron atom.

  2. B

    (B) Increasing order of ionic radii: Al Mg Na.

  3. C

    (C) Under identical conditions, in solid state, the density of potassium metal is more than density of sodium metal.

  4. D

    (D) The H-H bond is weaker than F-F bond.

Solution

(A) Second IE of C vs B. Removing the second electron from boron means pulling it from the stable 2s configuration of B (1s 2s), which requires extra energy. Removing the second electron from C (1s 2s 2p) takes it from a 2p orbital, which is easier. So IE(C) IE(B). Correct.

(B) Isoelectronic ionic radii. Al, Mg, Na all have the Ne configuration. As nuclear charge increases (Z = 11, 12, 13) the radius decreases, so Al Mg Na. Correct.

(C) Density of K vs Na. Although K has higher atomic mass, the increase in atomic volume from Na to K outpaces the mass increase, so density of K (0.86 g/cm) is actually less than density of Na (0.97 g/cm). Incorrect.

(D) H-H vs F-F bond strength. Bond dissociation energy of H-H is roughly 436 kJ/mol while F-F is only about 159 kJ/mol (weakened by lone-pair repulsion between the small F atoms). So H-H is stronger, not weaker. Incorrect.

Correct options are (A) and (B).

Practice more CHEM-II

Concept-wise practice with instant solutions on Fundamenthol.

Start practicing →