JEE Main 2019 — Maths solution | Fundamenthol

JEE Main2019Maths

Q.

For $x^{2} \neq = nπ + 1, n \in N$ (the set of natural numbers), the integral

$\int x \frac{2 sin ( x ^{2} - 1 ) - sin 2 ( x ^{2} - 1 )}{2 sin ( x ^{2} - 1 ) + sin 2 ( x ^{2} - 1 )}$ is equal to : (where c is a constant of integration)

A
$lo g_{e} sec (\frac{x ^{2} - 1}{2}) + c$
B
$lo g_{e} \frac{1}{2} sec^{2} (x^{2} - 1) + c$
C
$\frac{1}{2} lo g_{e} sec^{2} (\frac{x ^{2} - 1}{2}) + c$
D
$\frac{1}{2} lo g_{e} sec (x^{2} - 1) + c$

Solution

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