JEE Main 2019 — Maths solution | Fundamenthol

JEE Main2019Maths

Q.

If y = y(x) is the solution of the differential equation, $x \frac{d y}{d x} + 2 x = x^{2}$ satisfying $y (1) = 1$ then $y (\frac{1}{2})$ is equal to:

A
$\frac{7}{64}$
B
$\frac{13}{16}$
C
$\frac{49}{16}$
D
$\frac{1}{4}$

Solution

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