JEE Main 2019 — Physics solution

JEE Main2019Physics

Two masses m and $\frac{m}{2}$ are connected at the two ends of a massless rigid rod of length $l$ . The rod is suspended by a thin wire of torsional constant k at the centre of mass of the rod-mass system(see figure). Because of torsional constant k, the restoring torque is $τ = k θ$ for angular displacement 0. If the rod is rotated by $θ_{0}$ and released, the tension in it when it passes through its mean position will be:

A
$\frac{3 k θ _{0}^{2}}{l}$
B
$\frac{k θ _{0}^{2}}{2 l}$
C
$\frac{2 k θ _{0}^{2}}{l}$
D
$\frac{k θ _{0}^{2}}{l}$

Solution

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