JEE Main2019Maths
Q.
Equation of a common tangent to the circle, x2 + y2 – 6x = 0 and the parabola, y2 = 4x, is:
- A
2 y = 12 x + 1
- B
2 y = – x – 12
- C
y = x + 3
- D
y = 3x + 1
Solution

Equation of a common tangent to the circle, x2 + y2 – 6x = 0 and the parabola, y2 = 4x, is:
2 y = 12 x + 1
2 y = – x – 12
y = x + 3
y = 3x + 1
