JEE Main 2019 — Chemistry solution

JEE Main2019Chemistry

A solution of sodium sulfate contains 92 g of Na⁺ions per kilogram of water. The molality of Na⁺ions in that solution in mol kg^.1is:

Solution

92g of Na⁺ = $\frac{92}{23}$ = 4 moles

$M o l a l i t y$ = $\frac{n u mb er o f m o l es}{ma ss o f so l v e n t ( in k g )}$

= $\frac{4}{1}$ =4mol kg^-1

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