JEE Main 2019 — Maths solution | Fundamenthol

JEE Main2019Maths

Q.

The equation of the line passing through (–4, 3, 1), parallel to the plane x + 2y – z – 5 = 0 and intersecting the line $\frac{x + 1}{- 3} = \frac{y - 3}{2} = \frac{z - 2}{- 1}$ is:

A
$\frac{x + 4}{- 1} = \frac{y - 3}{1} = \frac{z - 1}{1}$
B
$\frac{x + 4}{3} = \frac{y - 3}{- 1} = \frac{z - 1}{1}$
C
$\frac{x + 4}{1} = \frac{y - 3}{1} = \frac{z - 1}{3}$
D
$\frac{x - 4}{2} = \frac{y + 3}{1} = \frac{z + 1}{4}$

Solution

← Back to full paper

Practice more Maths

Concept-wise practice with instant solutions on Fundamenthol.

Start practicing →