JEE Main 2019 — Maths solution | Fundamenthol

JEE Main2019Maths

Q.

For any $θ \in (\frac{π}{4}, \frac{π}{2}),$ the expression $3 (sin θ - cos θ)^{4} + 6 (sin θ + cos θ)^{2} + 4 sin^{6} θ$ equals:

A
13 – 4 cos⁶ $θ$
B
13 – 4 cos⁴ $θ$ + 2 sin² $θ$ cos² $θ$
C
13 – 4 cos² $θ$ + 6 cos⁴ $θ$
D
13 – 4 cos² $θ$ + 6 sin² $θ$ cos² $θ$

Solution

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