JEE Main 2019 — Physics solution | Fundamenthol

JEE Main2019Physics

Q.

Two point charges $q_{1} (10 μ C)$ and $q_{2} (- 25 μ C)$ are placed on the x-axis at x = 1 m and x = 4 m respectively. The electric field (in V/m) at a point y = 3 m on y-axis is, $[t ak e \frac{1}{4 π ε _{0}} = 9 \times 10^{9} N m^{2} C^{- 2}]$

A
$(63 \hat{i} - 27 \hat{j}) \times 1 0^{2}$
B
$(81 \hat{i} - 81 \hat{j}) \times 1 0^{2}$
C
$(- 81 \hat{i} + 81 \hat{j}) \times 1 0^{2}$
D
$(- 63 \hat{i} + 27 \hat{j}) \times 1 0^{2}$

Solution

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