JEE Main 2019 — Physics solution | Fundamenthol

JEE Main2019Physics

Q.

The energy associated with electric field is (U_E ) and with magnetic field is (U_B ) for an electromagnetic wave in free space, Then.

A
$U_{E} < U_{B}$
B
$U_{E} = \frac{U _{B}}{2}$
C
$U_{E} = U_{B}$
D
$U_{E} > U_{B}$
E

Solution

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