Fundamentholfundamenthol
JEE Main2019Physics
Q.

A force acts on a 2 kg object so that its position is given as a function of time as x = 3t2 + 5. What is the work done by this force in first 5 seconds? 

  1. A

    950 J

  2. B

    900 J

  3. C

    850 J

  4. D

    875 J

Solution

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