JEE Main 2019 — Physics solution

JEE Main2019Physics

A parallel plate capacitor with square plates is filled with four dielectrics of dielectric constants K₁ , K₂ , K₃ , K₄ arranged as shown in the figure. The effective dielectric constant K will be:

A
$K = \frac{( K _{1} + K _{2} ) ( K _{3} + K _{4} )}{2 ( K _{1} + K _{2} + K _{3} + K _{4} )}$
B
$K = \frac{( K _{1} + K _{2} ) ( K _{3} + K _{4} )}{K _{1} + K _{2} + K _{3} + K _{4}}$
C
$K = \frac{( K _{1} + K _{3} ) ( K _{2} + K _{4} )}{K _{1} + K _{2} + K _{3} + K _{4}}$
D
$K_{e q .} = \frac{K _{1} K _{2}}{K _{1} + K _{2}} + \frac{K _{3} K _{4}}{K _{3} + K _{4}}$

Solution

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