JEE Main 2019 — Physics solution | Fundamenthol

JEE Main2019Physics

Q.

Charge is distributed within a sphere of radius R with volume charge density $ρ (r) = \frac{A}{r ^{2}} e^{\frac{- 2r}{a}}$ , where A and a are constants. If Q is the total charge of this charge distribution, the radius R is:

A
$\frac{a}{2} lo g \frac{1}{1 - \frac{Q}{2 π a A}}$
B
$\frac{a}{2} lo g (1 - \frac{Q}{2 π a A})$
C
$a lo g (1 - \frac{Q}{2 π a A})$
D
$a lo g \frac{1}{1 - \frac{Q}{2 π a A}}$

Solution

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