JEE Main2019Math
Q.
Let the equations of two sides of a triangle be 3x – 2y + 6 = 0 and 4x + 5y – 20 = 0. If the orthocentre of this triangle is at (1, 1), then the equation of its third side is
- A
26x – 122y – 1675 = 0
- B
122y – 26x – 1675 = 0
- C
122y + 26x + 1675 = 0
- D
26x + 61y + 1675 = 0
Solution
