JEE Main2019Physics
Q.
A heat source at T= l03 K is connected to another heat reservoir at T=102 K by a copper slab which is 1 m thick. Given that the thermal conductivity of copper is 0.1 WK–1 m–1, the energy flux through it in the steady state is :
- A
90 Wm–2
- B
200 Wm–2
- C
65 Wm–2
- D
120 Wm–2
Solution

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