JEE Main 2019 — Math solution

JEE Main2019Math

$i f \frac{d y}{d x} + \frac{x}{cos ^{2} x} y = \frac{1}{cos ^{2}}, x \in (\frac{- π}{3}, \frac{π}{3}), an d$ $y (\frac{π}{4}) = \frac{4}{3},$ then $y (- \frac{π}{4})$ equals :