JEE Main2019Physics
Q.
At some location on earth the horizontal component of earth’s magnetic field is 18 × 10–6 T. At this location, magnetic needle of length 0.12 m and pole strength 1.8 Am is suspended from its mid-point using a thread, it makes 45° angle with horizontal in equilibrium. To keep this needle horizontal, the vertical force that should be applied at one of its ends is:
- A
1.3 × 10–5 N
- B
1.8 × 10–5 N
- C
6.5 × 10–5 N
- D
3.6 × 10–5 N
Solution

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