JEE Main 2019 — Physics solution | Fundamenthol

JEE Main2019Physics

Q.

Four equal point charges Q each are placed in the xy plane at (0, 2), (4, 2), (4, –2) and (0, –2). The work required to put a fifth charge Q at the origin of the coordinate system will be:

A
$\frac{Q ^{2}}{2 2 π ε _{0}}$
B
$\frac{Q ^{2}}{4 π ε _{0}} (1 + \frac{1}{3})$
C
$\frac{Q ^{2}}{4 π ε _{0}}$
D
$\frac{Q ^{2}}{4 π ε _{0}} (1 + \frac{1}{5})$

Solution

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