JEE Main 2019 — Physics solution | Fundamenthol

JEE Main2019Physics

Q.

The electric field of a plane polarized electromagnetic wave in free space at time t = 0 is given by an expression $E (x, y) = 10 \hat{j} cos [(6 x + 8 z)]$ The magnetic field $B (x, z, t)$ is given by : (c is the velocity of light)

A
$\frac{1}{c} (6 \hat{k} + 8 \hat{i}) cos [(6 x + 8 z - 10 c t)]$
B
$\frac{1}{c} (6 \hat{k} - 8 \hat{i}) cos [(6 x + 8 z + 10 c t)]$
C
$\frac{1}{c} (6 \hat{k} + 8 \hat{i}) cos [(6 x - 8 z + 10 c t)]$
D
$\frac{1}{c} (6 \hat{k} - 8 \hat{i}) cos [(6 x + 8 z - 10 c t)]$

Solution

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