JEE Main 2019 — Math solution | Fundamenthol

JEE Main2019Math

Q.

On which of the following lines lies the point of intersection of the line, $\frac{x - 4}{2} = \frac{y - 5}{2} = \frac{z - 3}{1}$ and

the plane, x + y + z = 2?

A
$\frac{x - 1}{1} = \frac{y - 3}{2} = \frac{z + 4}{- 5}$
B
$\frac{x + 3}{3} = \frac{4 - y}{3} = \frac{z + 1}{- 2}$
C
$\frac{x - 4}{1} = \frac{y - 5}{1} = \frac{z - 5}{- 1}$
D
$\frac{x - 2}{2} = \frac{y - 3}{2} = \frac{z + 3}{3}$

Solution

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