JEE Main2019Physics
Q.
A current of 2 mA was passed through an unknown resistor which dissipated a power of 4.4 W. Dissipated power when an ideal power supply of 11 V is connected across it is.
- A
11 × 10–5 W
- B
11 × 105 W
- C
11 × 10–3 W
- D
11 × 10–4 W
Solution

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