JEE Main2019Physics
Q.
A metal plate of area 1 × 10–4 m2 is illuminated by a radiation of intensity 16 mW/m2. The work function of the metal is 5 eV. The energy of the incident photons is 10 eV and only 10% of it produces photo electrons. The number of emitted photo electrons per second and their maximum energy, respectively, will be : [1 eV = 1.6 × 10–19 J]
- A
1014 and 10 eV
- B
1011 and 5 eV
- C
1010 and 5 eV
- D
1012 and 5 eV
Solution

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