JEE Main 2019 — Physics solution | Fundamenthol

JEE Main2019Physics

Q.

Consider the nuclear fission $N e^{20} \to 2 H e^{4} + C^{12}$ Given that the binding Ne²⁰, He⁴ and C¹² are, respectively, 8.03 MeV, 7.07 MeV and 7.86 MeV, identify the correct statement:

A
Energy of 12.4 MeV will be supplied
B
8.3 MeV energy will be released
C
Energy of 3.6 MeV will be released
D
Energy of 9.72 MeV has to be supplied

Solution

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