JEE Main2019Math
Q.
Let f\left( x \right) = \left\{ {\begin{array}{*{20}{c}} { - 1}{ - 2 \leqslant x < 0} \\ {{x^2} - 1,}{0 \leqslant x \leqslant 2} \end{array}} \right. and g(x) = | f(x)|+f(|x|). Then, in the interval (–2, 2), g is :-
- A
not differentiable at two points
- B
not differentiable at one point
- C
not continuous
- D
differentiable at all points
Solution
