JEE Main 2019 — Math solution | Fundamenthol

JEE Main2019Math

Q.

Let A = \,\left( {\begin{array}{*{20}{c}} 0{2q}r \\ pq{ - r} \\ p{ - q}r \end{array}} \right). If AA^T = I₃, then |p| is:

A
$\frac{1}{3}$
B
$\frac{1}{6}$
C
$\frac{1}{5}$
D
$\frac{1}{2}$

Solution

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