JEE Main 2019 — Math solution | Fundamenthol

JEE Main2019Math

Q.

If $\int \frac{1 - x ^{2}}{x ^{4}} d x = A (x) (1 + x^{2})^{m} + C,$ for a suitable chosen integer m and a function A(x), where C is a constant of integration, then (A(x))m equals:

A
$\frac{1 -}{3 x ^{3}}$
B
$\frac{1}{27 x ^{6}}$
C
$\frac{1}{9 x ^{4}}$
D
$\frac{- 1}{27 x ^{9}}$

Solution

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