JEE Main 2019 — Math solution | Fundamenthol

JEE Main2019Math

Q.

If y(x) is the solution of the differential equation $\frac{d y}{d x} + (\frac{2 x + 1}{x}) y = e^{- 2 x}, x > 0,$ where $y (1) = \frac{1}{2} e^{- 2}$ then

A
y(x) is decreasing in $(\frac{1}{2}, 1)$
B
$y (lo g_{e} 2) = \frac{lo g _{e} 2}{4}$
C
$y (lo g_{e} 2) = lo g_{e} 4$
D
y(x) is decreasing in (0, 1)

Solution

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