Fundamentholfundamenthol
JEE Main2019Physics
Q.

Ice at –20°C is added to 50 g of water at 40°C. When the temperature of the mixture reaches 0°C, it is found that 20 g of ice is still unmelted. The amount off ice added to the water was close to

(Specific heat of water = 4.2 J/g/°C

Specific heat of Ice = 2.1 J/g/°C  

Heat of fusion of water at 0°C = 334 J/g)

  1. A

    100 g

  2. B

    40 g

  3. C

    50 g

  4. D

    60 g

Solution

Heat lost by water = 50 × 40 = 2000 cal.

Let amount of ice be x g.

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