JEE Main2019Physics
Q.
An electric field of 1000 V/m is applied to an electric dipole at angle of 45°. The value of electric dipole moment is 10–29 Cm. What is the potential energy of the electric dipole?
- A
–9 × 10–20 J
- B
–10 × 10–29 J
- C
–7 × 10–27 J
- D
–20 × 10–18 J
Solution

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