JEE Main2019Physics
Q.
A 27 mW laser beam has a cross-sectional area of 10 mm2. The magnitude of the maximum electric field in this electromagnetic wave is given by: [Given permittivity of space = 9 × 10–12 SI units, Speed of light c = 3 × 10‑8 m/s]
- A
1.4 kV/m
- B
1 kV/m
- C
2 kV/m
- D
0.7 kV/m
Solution

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