JEE Main 2019 — Math solution | Fundamenthol

JEE Main2019Math

Q.

If $a - b - c 2 a 2 a 2 bb - c - a 2 b 2 c 2 cc - a - b = (a + b + c) (x + a + b + c)^{2}, x \neq = 0$ and $a + b + c \neq = 0,$ then x is

equal to :

A
2(a + b + c)
B
–(a + b + c)
C
abc
D
–2(a + b + c)

Solution

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