JEE Main2019MathQ.If ∫2x−1x+1dx=f(x)2x−1+C where C is a constant of integration, then f(x) is equal to :A31(x+1)B31(x+4)C32(x+4)D32(x−4)SolutionView solution← Back to full paperPractice more MathConcept-wise practice with instant solutions on Fundamenthol.Start practicing →