JEE Main 2019 — Math solution | Fundamenthol

JEE Main2019Math

Q.

The integral $\int_{\frac{π}{6}}^{\frac{π}{4}} \frac{d x}{sin 2 x ( tan ^{5} x + cot ^{5} x )}$ equals:

A
$\frac{1}{10} (\frac{π}{4} - tan^{- 1} (\frac{1}{9 3}))$
B
$\frac{1}{20} tan^{- 1} (\frac{1}{9 3})$
C
$\frac{π}{10}$
D
$\frac{1}{5} (\frac{π}{4} - tan^{- 1} (\frac{1}{3 3}))$

Solution

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