JEE Main 2019 — Math solution | Fundamenthol

JEE Main2019Math

Q.

Let $α$ and $β$ the roots of the quadratic equation $x^{2} sin θ - x (sin θ cos θ + 1) + cos θ = 0 (0 < θ < 4 5^{o}), α < β$ Then $n = 0 \sum \infty (α^{n} + \frac{( - 1 ) ^{n}}{β ^{n}})$ is equal to :

A
$\frac{1}{1 + cos θ} - \frac{1}{1 - sin θ}$
B
$\frac{1}{1 - cos θ} + \frac{1}{1 + sin θ}$
C
$\frac{1}{1 - cos θ} - \frac{1}{1 + sin θ}$
D
$\frac{1}{1 + cos θ} + \frac{1}{1 - sin θ}$

Solution

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