Fundamentholfundamenthol
JEE Main2019Math
Q.

Let C1 and C2 be the centres of the circles x2 + y2 – 2x – 2y – 2 = 0 and x2 + y2 – 6x – 6y + 14 = 0 respectively. If P and Q are the points of intersection of these circles, then the area (in sq. units) of the quadrilateral PC1 QC2 is 

  1. A

    4 

  2. B

    9

  3. C

    6

  4. D

    8

Solution

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