Fundamentholfundamenthol
JEE Main2019Chemistry
Q.

50 mL of 0.5 M oxalic acid is needed to neutralize 25 mL of sodium hydroxide solution. The amount of NaOH in 50 mL of the given sodium hydroxide solution is 

  1. A

    10 g 

  2. B

    4 g 

  3. C

    8 g 

  4. D

    20 g 

Solution

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