JEE Main 2019 — Chemistry solution

JEE Main2019Chemistry

Given

(i) C (graphite) $+ O_{2} (g) \to C O_{2} (g); Δ r H^{Θ} = x k J m o l^{- 1}$

(ii) C (graphite) $+ \frac{1}{2} O_{2} (g) \to C O_{2} (g); Δ r H^{Θ} = y k J m o l^{- 1}$

(iii) $C O (g) + \frac{1}{2} O_{2} (g) \to C O_{2} (g); Δ r H^{Θ} = z k J m o l^{- 1}$

Based on the above thermochemical equations, find out which one of the following algebraic relationships is correct?

Solution

According to Hess’s law, the enthalpy change of a reaction does not depend on the number of steps involved in the reaction.

** in reaction ii, Product should be CO (gas) instead of CO₂(gas).

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