JEE Main 2019 — Math solution | Fundamenthol

JEE Main2019Math

Q.

For $x > 1,$ if $(2 x)^{2 y} = 4 e^{2 x - 2 y}$ , then $(1 + lo g_{e} 2 x)^{2} \frac{d y}{d x}$ is equal to:

A
log_e 2x
B
x log_e 2x
C
$\frac{x lo g _{e} 2 x + lo g _{e} 2}{x}$
D
$\frac{x lo g _{e} 2 x - lo g _{e} 2}{x}$

Solution

← Back to full paper

Practice more Math

Concept-wise practice with instant solutions on Fundamenthol.

Start practicing →