JEE Main2019MathQ.The integral ∫cos(logex)dx is equal to (where C is a constant of integration) Ax[cos(logex)−sin(logex)]+CB2x[cos(logex)+sin(logex)]+CC2x[sin(logex)−cos(logex)]+CDx[cos(logex)+sin(logex)]+CSolutionView solution← Back to full paperPractice more MathConcept-wise practice with instant solutions on Fundamenthol.Start practicing →