JEE Main 2019 — Physics solution | Fundamenthol

JEE Main2019Physics

Q.

In a radioactive decay chain, the initial nucleus is $_{90}^{232} T h$ . At the end there are 6 $α$ -particles and 4 $β$ -particles which are emitted. If the end nucleus is $_{Z}^{A} X$ , A and Z are given by:

A
A = 200; Z = 81
B
A = 202; Z = 80
C
A = 208; Z = 80
D
A = 208; Z = 82

Solution

232 – 6 × 4 = A

A = 208

Z = 90 – 6 × 2 + 4 × 1

= 82

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