JEE Main2019Math
Q.
If A = \left[ {\begin{array}{*{20}{c}} 1{\sin \theta }1 \\ { - \sin \theta }1{\sin \theta } \\ { - 1}{ - \sin \theta }1 \end{array}} \right]; then for all det (A) lies in the interval :
- A
- B
- C
- D
Solution
