JEE Main 2019 — Physics solution | Fundamenthol

JEE Main2019Physics

Q.

A simple harmonic motion is represented by : $y = 5 (sin 3 π t + 3 cos 3 π t)$ cm The amplitude and time period of the motion are:

A
10cm, $\frac{2}{3}$ s
B
5cm, $\frac{2}{3}$ s
C
10cm, $\frac{3}{2}$ s
D
5cm, $\frac{3}{2}$ s

Solution

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