JEE Main2019MathQ.Let y = y(x) be the solution of the differential equation, xdxdy+y=xlogex,(x>1).if2y(2)=loge4−1, then y(e) is equal toA4e2B−2eC−2e2D4eSolutionView solution← Back to full paperPractice more MathConcept-wise practice with instant solutions on Fundamenthol.Start practicing →