JEE Main 2019 — Physics solution

JEE Main2019Physics

To double the covering range of a TV transmission tower, its height should be multiplied by:

Solution

$d = 2 h R ∴ F or d^{'} t o b e 2 d \frac{2 d}{d} = \frac{2 h ^{'} R}{2 h R} \Rightarrow 4 h = h^{'}$

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