JEE Main 2019 — Math solution | Fundamenthol

JEE Main2019Math

Q.

If $2 y = (cot^{- 1} (\frac{3 cos x + sin x}{cos x - 3 sin x}))^{2}, x \in (0, \frac{π}{2})$ then $\frac{d y}{d x}$ is equal to :

A
$2 x - \frac{π}{3}$
B
$x - \frac{π}{6}$
C
$\frac{π}{3} - x$
D
$\frac{π}{6} - x$

Solution

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