JEE Main 2019 — Math solution | Fundamenthol

JEE Main2019Math

Q.

The integral $1 \int e {(\frac{x}{e})^{2 x} - (\frac{e}{x})^{x}} lo g_{e} x d x$ is equal to

A
$\frac{3}{2} - e - \frac{1}{2 e ^{2}}$
B
$- \frac{1}{2} + \frac{1}{e} - \frac{1}{2 e ^{2}}$
C
$\frac{1}{2} - e - \frac{1}{2 ^{e}}$
D
$\frac{3}{2} - \frac{1}{e} - \frac{1}{2 e ^{2}}$

Solution

← Back to full paper

Practice more Math

Concept-wise practice with instant solutions on Fundamenthol.

Start practicing →